Webnum = 1234 thousands = num // 1000 hundreds = (num % 1000) // 100 tens = (num % … WebLet’s divide 295 by 4 and the remainder is 3. Thus, the last digit of 7 295 is equal to the last digit of 7 3 i.e. 3. Let’s divide 158 by 4, the remainder is 2. Hence the last digit will be 9. Therefore, unit’s digit of (7 925 X 3 158) …

How to find the sum of digits of a number in Python

WebHi, im new to Python so im doing a number of exercises in class in order to learn more and more. Im trying to do one where im supposed to be Separating ones, tens, hundreds, and thousands from each other, and dont print nothing if the number equals zero. Lets say: 104 1 hundred 4 unit i came up with this : WebMay 21, 2024 · 3 Answers Sorted by: 4 251 72 ≡ 1 ( mod 10) 3547 153 ≡ 7 153 ( mod 10) Cyclic sequence of 7 n is as follows. 7 1 = 7 7 2 = 49 7 3 = 343 7 4 = 2401 Lets divide 153 by 4 and the remainder is 1. Thus, the unit digit of 7 153 is equal to the unit digit of 7 1 = 7. Hence the unit digit of 3547 153 × 251 72 is equal to 7. 264 102 ≡ 4 102 ( mod 10) jessica whitehorse video

How to find the number of digits in a given number using Python?

WebFeb 26, 2024 · You should use regular expressions, grouping together what you want to find out: import re s = "17GB" match = re.match (r"^ ( [1-9] [0-9]*)\s* (GB MB KB B)$", s) if match: print "Number: %d, unit: %s" % (int (match.group (1)), match.group (2)) Change the regex according to what you want to parse. WebNov 17, 2014 · By the previous method, the last two digits of \(21^{72}\) = 41 (tens digit = 2 × 2 = 4, unit digit = 1) So here's the rule for finding the last two digits of numbers ending in 3, 7 and 9: Convert the number till the number gives 1 as the last digit and then find the last two digits according to the previous method inspector manara season 2 imdb